(2x-3)^2-5x=4x^2-252

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Solution for (2x-3)^2-5x=4x^2-252 equation: 



(2x-3)^2-5x=4x^2-252

We move all terms to the left:

(2x-3)^2-5x-(4x^2-252)=0

We add all the numbers together, and all the variables

-5x+(2x-3)^2-(4x^2-252)=0

We get rid of parentheses

-4x^2-5x+(2x-3)^2+252=0

We move all terms containing x to the left, all other terms to the right

-4x^2-5x+(2x-3)^2=-252

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